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3 years ago

12

21/5 + 4/3 - 1/2 what is the answer

1 answer:

Cerrena [4.2K]3 years ago

6 0

Answer:

151/30

Step-by-step explanation:

hopefully it is clear and understandable...and visible

:)

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Please i need help with 4th grade math please write the answer and shiw the solution hownto solve the problem step by step.thank

julia-pushkina [17]

Answer:

110

Step-by-step explanation:

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2 years ago

Read 2 more answers

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

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3 years ago

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jenyasd209 [6]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

y= -3/4x+3

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Esther wants to know if the number of words on a page in her language arts book is generally more than the number of words on a

pychu [463]

<span>No, because the mean is larger in the social studies book</span>

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3 years ago