Find all of the zeros of f(x) = 5x^2 +40x-100
2 answers:
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Answer:
w-2u-v
Step-by-step explanation:
Given are three vectors u, v and w.
In R^2 we treat first element as x coordinate and 2nd element as y coordinate.
Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.
b)
We have to find the values of a and b
]
Equate the corresponding terms
Divide II equation by 2 to get
Eliminate a
-5 = 5b: b=-1
a=-2
Hence
w = 2u-v