The x-coordinate of the vertex of a parabola y = ax^2 + bx + c is x = -b / (2a).
Here, a = -3 and b = -10, so the x-coord of the vertex is x = 10 / (2*-3), or
x = 10 / (-6) = -5/3
and so the y-coordinate is y = -3(-5/3)^2 - 10(-5/3) = 25/3
The vertex of this parabola is (-5/3, 25/3). (answer)
I got 3x^2 + 12x + 4. I recommend you verify my answer, so you have to combine like terms in the first expression then add all the expressions.
The answer would be 3.75 or 15/4.
Answer:
(-2,8)
Step-by-step explanation:
-7x-2y = -2
-6x+8y = 76
Multiply the first equation by 4 to eliminate y
-28x -8y = -8
Then add it to the second equation
-28x -8y = -8
-6x+8y = 76
--------------------
-34x = 68
Divide by -34
-34x/-34 = 68/-34
x = -2
Now substitute back into one of the equations to find y
-6x +8y = 76
-6(-2) +8y = 76
12+8y = 76
Subtract 12 from each side
12+8y-12 = 76-12
8y = 64
Divide each side by 8
8y/8 = 64/6
y=8
(-2,8)