Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
If the first question mark is 3 then the next is 13 than the next still 13 and the right one 26 and then lastly x is equally to 2
Or
3x+9+10x=33
13x+9=33
13x=26
X=2
Answer: 44
solution: x+(x+2)+(x+4)+(x+6)+(x+8)=200
5x+20=200
5x=180
x=36
5th number - x+8=36+8=44
Answer: 28
Step-by-step explanation: you have to add 21 + 7 because your counting up from -7 to 21
I'm not quite sure what you asking here but if your asking how to answer it in "math terms" than I'll be happy to explain :)
So "times" means multiply and "increase" means add so righting this in math terms would be
6x + 5
because it's six times "a number" which you can replace with x!
Let me know if you have any questions :3
