Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
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Since 3 cannot equal 0, we can focus on the following:
x^2 - 7/4 x =-4
This completes the assignment (describe Joe's steps up to this point).
If you wish to go further:
Next, take HALF of the coefficient of x and square your result:
(-7/[4][2])^2 = 49/64
Add this to both sides of </span>x^2 - 7/4 x =-4: <span>x^2 - 7/4x + 49/64 =-4+49/64
Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64
Simplify the right side by combining these terms: -207/64
Then x-7/8 = plus or minus (1/8)sqrt(-207)
Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or
7 plus or minus i*√207
x = ----------------------------------
8
(6x7) = 47
(6x-7) = -42 -- This is because you are multiplying two differently signed numbers, the product will be negative.
<span>x^2 = 81
x = </span>±√81
x = ±9<span>
x^2 = -9 no solutions
x^2 = 20
x = </span>±√20
x = <span>±2</span>√5<span>
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Formula :
Base²= Hypotenuse² - Perpendicular ²
Remember the a² in formula has nothing to do with the a we have to find. :)
Do you have a typo? ; < this maybe
