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Ann [662]
2 years ago
10

Find the distance between each pair of numbers on the number line; then find the coordinate of their midpoint.

Mathematics
2 answers:
dexar [7]2 years ago
8 0

9514 1404 393

Answer:

  • distance: 31/24 = 1 7/24
  • midpoint: -1/48

Step-by-step explanation:

The distance between the points is the difference of their coordinates:

  5/8 -(-2/3) = 15/24 +16/24 = 31/24 = 1 7/24

__

The midpoint is the average of the two coordinates: half their sum.

  (5/8 +(-2/3))/2 = (15/24 -16/24)/2 = (-1/24)(1/2) = -1/48

quester [9]2 years ago
4 0

Answer:

d = 1 7/24 or 31/24;  midpoint would be half of that,or 31/48

Step-by-step explanation:

Since distance is absolute value, add 2/3 and 5/8 to get the entire distance.  Midpoint is that distance divided by 2.

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-2.7+17.8+29.5+8.9=?
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2 years ago
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A nature museum has 2008 specimens of early birds, some with 222 wings and some with 444 wings. The specimens have a total of 40
ludmilkaskok [199]

Let's assume

number of birds with 2 wings is x

number of birds with 4 wings is y

A nature museum has 2008 specimens of early birds

so,

x+y=2008

Total of wings of 2 wings bird =2x

Total of wings of 4 wings bird =4y

The specimens have a total of 4384 wings

so, we get

2x+4y=4384

we can divide both sides by 2

x+2y=2192

so, we get system of equations as

x+y=2008

x+2y=2192

we can solve for x and y

We can subtract both equations

2008-y+2y=2192

y=184

x=2008-184

x=1824

y=184,\:x=1824

so,

number of birds with 2 wings is 1824

number of birds with 4 wings is 184.............Answer



5 0
3 years ago
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
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Vinil7 [7]

Answer:

Step-by-step explanation:

to find x we can use tangent function

tan 31= x/9

0.60=x/9

x=0.60*9=5.4 choice B

8 0
2 years ago
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