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Mrac [35]
3 years ago
6

Simplify the expression so there is only one positive power for each base. ​

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

Option (A)

Step-by-step explanation:

The given expression is,

(5^{-2}\times 4^{-4})^{-2}

Since x^{-1}=\frac{1}{x} and \frac{1}{x^{-1}}=x

5^{2}=\frac{1}{5^{-2}}

4^{2}=\frac{1}{4^{-2}}

Therefore, (5^{-2}\times 4^{-4})^{-2}=\frac{1}{(5^{-2}\times 4^{-4})^{2}}

                                         =\frac{1}{(5^{-2})^2\times (4^{-4})^2}

                                         =\frac{1}{5^{-4}\times 4^{-8}}

                                         =\frac{1}{5^{-4}}\times \frac{1}{4^{-8}}

                                         =5^{4}\times 4^{8}                            

Option (A) will be the answer.                                          

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3 years ago
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Since this is a quadratic equation, subtract 84 from both sides so that it is set = to zero.
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To check the answer:
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Step-by-step explanation:

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