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valentina_108 [34]
3 years ago
9

I really need help in this 7th grade math

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

the awnser is 28

Step-by-step explanation:

the little 2 mean you times the 3 by it so it's 1+6. which is 7 and 18+2 is 20 and 20+7 is 28

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Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

7 0
4 years ago
In triangle JKL, m of angle J = 90, m of angle K = 30, and m of angle L = 60. Which of the following statements about triangle J
Lynna [10]

Answer:

option C. KL=2*JL

option D. JK=\frac{\sqrt{3}}{2}*KL

option F. JK=\sqrt{3}*JL

Step-by-step explanation:

step 1

we know that

In the right triangle JKL

sin(30\°)=\frac{JL}{KL}

sin(30\°)=\frac{1}{2}

so

\frac{1}{2}=\frac{JL}{KL}

KL=2*JL

step 2

cos(30\°)=\frac{JK}{KL}

cos(30\°)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=\frac{JK}{KL}

JK=\frac{\sqrt{3}}{2}*KL

step 3

tan(30\°)=\frac{JL}{JK}

tan(30\°)=\frac{1}{\sqrt{3}}

\frac{1}{\sqrt{3}}=\frac{JL}{JK}

JK=\sqrt{3}*JL

7 0
4 years ago
Please help me asap!!!!
Ghella [55]
Milli = .001
deci = .01
centi = 1
kilo = 1000
6 0
4 years ago
First determine if the given is a ordered pair (-1.7): 4x + y = 3. 2x-y=3​
Mrrafil [7]

Answer:

i didnt mean to click on this and it wont let me exit out im sorry

Step-by-step explanation:

4 0
3 years ago
Is this correct i im not sure :(
forsale [732]

Answer:

Not sure exactly were they go, but i can tell you that 5/6 goes between 0 and 1. Since its not a mixed fraction it cant possibly be over at 5. Like i said sorry i couldn't say exactly were to put them.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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