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3 years ago

Simplify | 4-9 | A)13 B)5 C)-5 D)-13

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

The answer is 5 because 4-9=-5 and the absolute value cancels the negative

ElenaW [278]3 years ago

6 0

Answer: The Answer is -5

Step-by-step explanation:

Ok so we have the numbers 4 and 9 and in this equation we are simplifing them by doing 4-9.

this is easy, we do 4-9 which is -5, you can even check this on a calculator. Plz follow me on twitch, InfernoEliteGamingYT21

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(3-p)^2<br> How to solve this steps

Zanzabum

Answer:

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4 years ago

Simplify ^3 sq try (-0.05)^24

Bogdan [553]

Answer:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

so option D is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{\left(-0.05\right)^{24}}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}$

$=\left(-0.05\right)^{24\cdot \frac{1}{3}}$

$=\left(-0.05\right)^8$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=0.05^8$

Hence, the simplification will be:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

Therefore, option D is correct.

7 0

3 years ago

over the next 30 years,some estimates place the worlds population going from roughly 7.2 billion people in the world to 10 billi

vredina [299]

Answer:

Current impact in pollution units per day=21.6 billion pollution units per day

Step-by-step explanation:

1 person consumes 3000 kilo-calories per person

Current population=7.2 billion people

Total calories the entire population produces=(7.2 billion×3000)

1000 kilo-calories causes= 1 pollution unit

To get the impact of the entire population=(7.2 billion×3000)/1000=21.6 billion pollution units per day

8 0

3 years ago

If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32

velikii [3]

Number of multiples of 7 up to 1337: $\left\lfloor\dfrac{1337}7\right\rfloor=191$
Number of multiples of 11 up to 1337: $\left\lfloor\dfrac{1337}{11}\right\rfloor=121$
Number of multiples of 77 up to 1337: $\left\lfloor\dfrac{1337}{77}\right\rfloor=17$

This means there are $191+121-17=295$ distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k$

which can be computed using the well-known formula,

$\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2$

So you have

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762$

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3 years ago

What is the perpendicular height of a cone that has a base with a diameter of 14 cm and whose sides make an angle of 72 with the

lord [1]

The answer is 21.5 cm

4 0

4 years ago