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vampirchik [111]
3 years ago
5

What is 3.2 times 10^negative 5 times 1.5 times 10^3 in scientific notation​

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0
4.8 x 10^-2
You can do this without a calculator
Explanation:
(3.2 x 10^-5) x (1.5 x 10^3)
First, you multiply 3.2 by 1.5 to get 4.8
Next, you add the exponents together: -5 + 3 = -2
Now, put everything into one answer (the 10 stays the same): 4.8 x 10^-2
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A perpendicular line is a line that meets a 90 degree angle.

Step-by-step explanation:

Think of the letter L

the top stick of the letter is perpendicular to the bottom stick and it makes a 90 degree angle.

Thats the best way I can explain it.

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What percent is 52 out of 200
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Solve the equation -x=2-3x+3 and show your work/step by step
Debora [2.8K]

Answer:

x = ​\frac{5}{2}

Decimal Form: 2.5

Step-by-step explanation:

1) First, you have to simplify 2 − 3x + 3 to −3x + 5.

−x = −3x + 5

2) Next, You add 3x to both sides.

−x + 3x = 5

3) Then, Simplify −x + 3x to 2x.

2x = 5

4) Lastly, you divide both sides by 2 and you're done!

x = \frac{5}{2}

Decimal Form: 2.5

4 0
4 years ago
What is the difference?<br> -6-[11)<br> -17<br> 5<br> 5<br> 17
Eduardwww [97]

Answer:

-17

Step-by-step explanation:

You have to simplify the expression!

5 0
3 years ago
There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b
WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

                         a>b>c

a>b>c>d\\\implies x

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together =O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) \frac{c}{3}

Using (1)

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}

Similarly

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}

So,

\frac{c}{3}

3 0
3 years ago
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