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Paul [167]
3 years ago
6

If 258 cars pass through an intersection in six hours, how many cars pass through the intersection every two hours?

Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

86

Step-by-step explanation:

258/6=43

43x2=86

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Jeremy bought postcards on a trip. He
noname [10]

Answer:

T = total #

T = 5 (to the aunt) + 1/2 (T - 5) (to his friends) + 1 (to his sister) + 4 (left)

T = 5 + 1/2 (T - 5) + 1 + 4

T = 10 + 1/2 (T - 5)

2T = 20 + (T - 5)

2T = 20 + T - 5

2T = 15 + T

T = 15

Step-by-step explanation:

5 0
2 years ago
Solve the system of equations.<br> 2y+7x=−5<br> 5y−7x=12<br> ​
3241004551 [841]

We can solve this by substitution method.

Look at the second equation. If we rearrange to find 7x, we can substitute in the value into the first equation.

5y-7x=12

5y-7x-12=0

5y-12=7x

Therefore, 7x=5y-12

Now replace the 7x in the first equation with 5y - 12:

2y+7x=-5 (substitute in 7x = 5y - 12)

2y+(5y-12)=-5

7y-12=-5

7y=7

y=1

Now that we know y, we can find x by substituting in y = 1 into any equation we want. I will use the equation: 7x = 5y - 12

7x=5y-12 (substitute in y = 1)

7x=5(1) -12

5x=5-12

7x=-7

x=-1

__________________________________________________________

<u>Answer:</u>

<u></u>y=1\\x=-1<u></u>

4 0
3 years ago
18 Andy flies from the UK to Japan.
kotykmax [81]

Answer:

<u>Leila pays more</u> than Andy to fly from the UK to Australia.

Step-by-step explanation:

Given:

Andy flies from the UK to Japan.

His plane ticket costs £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

Leila flies from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

<u>Now, to find Andy or Leila who pays more to fly from the UK to Australia.</u>

Andy flies from the UK to Japan.

His plane ticket costs = £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

So, by using conversion factor we convert Japanese Yen to £.

140 = £1

70140 = 70140\div 140=\£501.

His plane ticket costs = £501.

Now, adding both the cost of tickets:

501+554=\£1055.

Andy total pays fly from the UK to Australia is £1055.

Now, to get the cost of plane ticket of Leila from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

So, by using conversion factor:

1 Australian dollar = £0.62

1860 Australian dollar = 1860\times 0.62=\£1153.2

Her plane ticket costs is £1153.2.

<u><em>As, we see that cost of plane ticket of Andy is £1055 and cost of plane ticket of Leila is £1153.2.</em></u>

<em>Thus, Leila pays more.</em>

Therefore, Leila pays more than Andy to fly from the UK to Australia.

4 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
Is what I have correct answer right away 100 points!!!!!
Semmy [17]
That's correct, because I learned it in math already


7 0
2 years ago
Read 2 more answers
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