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Alenkinab [10]
3 years ago
7

A zoo orders food in bulk for it's animals. they order enough fresh fruit to last 10 days, enough fresh vegetables for 7 days, a

nd enough dried insects for 5 days. if they last ordered fresh fruit, fresh vegetables, and dried insects on January 1, in how many days will they need to order all three items on the same day?
A) 65 days
B) 50 days
C) 70 days
D) 35 days​
Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

The answer to this question is C.) 70 Days

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I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
Pls help! need answer ASAP!!
yuradex [85]

Answer:

c because if you subtract

7 0
3 years ago
She decides to change the length of the top of the top of the trapezoid shaped garden from 32 to 24 ft. Which expression finds t
gulaghasi [49]

Answer:

<h3>The change in the scale factor is \frac{3}{4} ft</h3>

Step-by-step explanation:

Given that Sienna planned a trapezoid-shaped garden.

And She decides to change the length of the top of the trapezoid-shaped garden from 32 ft to 24 ft.

Let Old length of the top be 32 ft

Let New length of the top be 24 ft

Scale factor =\frac{New length}{old length}

Scale factor = \frac{24}{32}

=\frac{3}{4} ft

<h3>∴ the change in the scale factor is \frac{3}{4} ft</h3>
7 0
4 years ago
There are 100 pieces of candy in a
PIT_PIT [208]

Answer:

d

Step-by-step explanation:

because 100*9 is 900

4 0
3 years ago
Read 2 more answers
Make a box and whiskers plot of the data. average temperature in Pittsburgh in June 79,70,73,84,83,88,75,72,76,68,68,79,84,74,75
aliya0001 [1]
The box-and-whisker plot is attached.

We first order the data from least to greatest:
67,68,68,69,70,72,73,74,75,75,76,78,79,79,80,83,84,85,85,88

Now we find the median.  Since there are 20 data values, the median is between 75 and 76:
(75+76)/2 = 151/2 = 75.5

Now we find the Lower Quartile (LQ).  We do this by finding the median of the lower half of data (from the median down).  There are 10 values here; the median is between 70 and 72:
(70+72)/2 = 142/2 = 71

Find the Upper Quartile (UQ).  Do this by finding the median of the upper half of data (from the median up).  There are 10 values here; the median is between 80 and 83:
(80+83)/2 = 163/2 = 81.5

The middle bar of the box is over the median.  The left hand side of the box is over LQ, and the right hand side of the box is over UQ.  Now we draw a whisker from the box to the highest value, 88, and from the box to the lowest value, 67.

7 0
3 years ago
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