Lian has Z pennies. How many dollars does she have,

mina [271]

The highest point over the entire domain of a function or relation is absolute maximum whereas lowest point under the entire function is absolute minimum....

5 0

3 years ago

PLA HELP I'LL MARK BRAINLEST

Contact [7]

Answer:

X=55

Step-by-step explanation:

7 0

3 years ago

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Statistics??? Construct a 95% confidence interval for the population mean. Assume the population has a normal distribution. A sa

antiseptic1488 [7]

Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.

At the 95% confidence level, the confidence interval is
$( \mu - 1.96\frac{\sigma}{ \sqrt{n} } ,\, \mu + 1.96\frac{\sigma}{ \sqrt{n} })$

1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)

Answer: ($2823.29, $3416.71)

6 0

3 years ago

The park near John's house is being sprayed for mosquitoes. He and his neighbor are roping off the park so kids don't go near th

Gennadij [26K]

If you would like to know how much rope do they need, you can calculate this using the following steps:

42 yards * 2 + 36 yards * 2 = 42 * 2 + 36 * 2 = 84 + 72 = 156 yards

They will need 156 yards long rope.

4 0

3 years ago

Question 20 not yet answered marked out of 1.00 not flaggedflag question question text luna created a trash can in the shape of

Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

1.

$b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336$

Then you can conclude that ∠B is obtuse (because $\cos \angle B$ ) and m∠B=110°.

2.

$c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871$ .

Then you can conclude that ∠C is acute (because $\cos \angle C>0$ ) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

3 0

3 years ago