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MArishka [77]
3 years ago
6

Assume a color display using 8 bits for each of the primary colors (red, green, blue) per pixel and a frame size of 1280 × 1024.

What is the minimum size in bytes of the frame buffer to store a frame?
Mathematics
1 answer:
elixir [45]3 years ago
5 0

-8bits is equivalent yo 1 byte

-bit is(0 or 1)

So each pixel requires 3 bytes

Primary colors are RGB(red,green and blue),so each color represent one byte.

The frame size is:

1280×1024=1310720 pixels

So that the frame contained 1310720 pixels

The size of the frame buffer is equal to the product of RGB and frame pixels:

=3 × 1310720

=3932160 bytes

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Y=f(×)=9×<br> Find f(×) when x =1/2
mojhsa [17]
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<em><u>Solution:</u></em>

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y = f(x) = 9x

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We can solve by substituting x = 1/2 in given function

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