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2 years ago

Let f(x)=2x squared - 3x+8 what is the value of f(-4)

Mathematics

1 answer:

Illusion [34]2 years ago

5 0

Answer:

f(x) = 52

Step-by-step explanation:

f(x) does the same things as y, so when you get your answer, think of it as the value for y when x = - 4

The second thing you should know is that wherever you see an x on the right, you put in - 4

Let x = - 4

y = 2x^2 - 3x + 8

y = 2(-4)^2 - 3(-4) + 8

y = 2*16 - (-12) + 8

y = 32 + 12 + 8

y = 52

Be careful how you hand - 3x when -4 is put in for x. -3(-4) = 12 not - 12

f(-4) = 52

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Given the kite below, if NO = 5 and OM = 12, what is the value of NM?

tester [92]

Answer:

NM = 13

Step-by-step explanation:

pythagorean theorem: $a^{2} + b^{2} = c^{2}$

a or NO = 5

b or OM = 12

c or NM = ?

plug in what is known:

⇒ $5^{2} + 12^{2} = c^{2}$

⇒ $25 + 144 = c^{2}$

⇒ 169 = $c^{2}$

square root each side of the equation:

⇒ $\sqrt{169} = \sqrt{c^{2} }$

solve:

⇒ 13 = c

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2 years ago

The diagonals of this rhombus are 8 and 16 units long. Their intersection creates four right angles, two 4-unit-long segments, a

Roman55 [17]

Answer:

$64\ \text{sq. units}$

Step-by-step explanation:

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Length of one diagonal is 8 units and the other diagonal is 16 units

Area is given by

$A=\dfrac{8\times 16}{2}\\\Rightarrow A=64\ \text{sq. units}$

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Another approach is the diagonals have created 4 triangles where the base and is height is either 4 units long or 8 units long so the area of the rhombus would be the area of the 4 triangles.

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