Answer:
3 students are eating lunches other than salads and sandwiches.
Step-by-step explanation:
To solve this you know that there are 18 students in the cafeteria and 1/6 of them are eating salads and 2/3 are eating sandwiches right? So you would have to think about what 1/6 of 18 is so you know how many students are eating salads, and 1/6 of 18 is 3 so there are 3 students eating salads. Now, you have to find out how many students are eating sandwiches, so you need to know what 2/3 of 18 is. 2/3 of 18 is 12 so now you also know that there are 12 students eating sandwiches. Next, you have to add 12 and 3 and you get 15. Since you know that there are 18 students in the cafeteria, you have to subtract 18 by 15, and you should get 3. So 3 students are eating lunches other than salads or sandwiches.
Hope this helps you! :D
Answer:
25
Step-by-step explanation:
144/60 = 2.4
60/2.4 = x
x = 25
You can tell when you cant draw an even L shaped figure at the intersects of the bottom and the side. 90 degrees. But there are many different ways that may make more sense. Happy to help:)
Answer:
Since on July 9, Mifflin Company receives a $ 10,200, 90-day, 6% note from customer Payton Summers as payment on account, to determine what entry should be made on July 9 to record receipt of the note the following calculation must be performed :
90 days = 3 months
6/12 x 3 = 1.5%
10,200 x 1,015 = 10,353
Therefore, a debt cancellation for $ 10,200 must be made in the company's accounting records, plus an interest generation for $ 153, which will be justified by the cash income of $ 10,353.
Answer:
see the attachments for the two solutions
Step-by-step explanation:
When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.
When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.
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Here, the law of sines can be used to solve the triangle:
A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°
B = 180° -70° -A = 31.81° or 8.19°
b = 24·sin(B)/sin(70°) = 13.46 or 3.64
