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2 years ago

Find AB given A (5,-3) and B(-11, - 5).

Mathematics

2 answers:

vitfil [10]2 years ago

8 0

Answer:

yes

Step-by-step explanation:

d f xcdg

Lorico [155]2 years ago

5 0

Answer:

maybe uh forgot to copy complete question.

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6(3u+4) please help I am in a classwork

frozen [14]

Answer:

18u+24

Step-by-step explanation:hope this helps xxx

7 0

2 years ago

Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9

faust18 [17]

Answer:

-5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

-5 with multiplicity 3
+9 with multiplicity 2
-1

4 0

2 years ago

Almost there .......AAAAHHhH

madreJ [45]

Answer:

12/46

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A path 2.5m wide is running outside a square field whose side is 45m. Determine the area of the path.

aliya0001 [1]

Answer:

The area of the path would be 231.25 squared meters.

Step-by-step explanation:

Consider the path as 45m (the field's area), then add 2.5m to all of the sides. You'll get 47.5m on all sides. Then you do 47.5² to get 2256.25 squared meters. After that, you'll remove the area of the squared field. To do this, do 45m². By doing this, you'll get 2025 squared meters. Lastly, to finish up the question, do 2256.25 - 2025. This would get you 31.25 squared meters, the answer.

4 0

3 years ago

The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

Let $\mu$ = average sodium content.

So, Null Hypothesis, $H_0$ : $\mu$ = 1100 milligrams {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 1100 milligrams {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample average sodium content = 1088.64 milligrams

s = sample standard deviation = 234.12 milligrams

n = sample of packages of Oriental Spice Sauce = 40

So, test statistics = $\frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}$ ~ $t_3_9$

= -0.307

The value of z test statistics is -0.307.

Since, in the question we are not given the level of significance so we assume it to be 5%. Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0

3 years ago