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skelet666 [1.2K]
4 years ago
10

25 POINTS: In 1960, 21.5% of U.S. households did not have a telephone. This statistic decreased by 75.8% between 1960 and 1990.

In 1990, what percent of U.S. households had a telephone?
Mathematics
1 answer:
dem82 [27]4 years ago
7 0

Answer: 94.8 % (approx)

Step-by-step explanation:

Let the total household in the U.S is x,

⇒ The total household who did not have a telephone in 1960 = 21.5 % of x

= 0.215 x

According to the question,

The total household who do not have a telephone in 1990 = 75.8 % less than the household in 1960 who did not have the cell phone,

= (100-75.8)% of 0.215x

= 24.2 % of 0.215x

= 0.05203x,

⇒ The household in 1990 who had a telephone = x - 0.05203x = 0.94797x

Hence, the percentage of household who has a telephone in 1990

= \frac{0.94797x}{x}\times 100

= 94.797\%\approx 94.8\%

⇒ Around 94.8% household had telephone in the US in 1990.

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ra1l [238]

Answer:

40.625%

Step-by-step explanation:

This is a very simple question.

We have to understand converting word equations to algebraic ones.

"is" means "="

"of" means "*"

So, we can write:

39 = what percent * 96

Now, we let "what percent" be "p" and solve the equation for p:

39 = P * 96

So,

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Converting this decimal to percentage means multiplying by 100, so we have:

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4 years ago
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Pavel [41]

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Step-by-step explanation:

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Step-by-step explanation:

I believe this is it. Hope this helped!

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