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AnnZ [28]
3 years ago
5

Please please please help brooo :(((

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

when the 9x moved to the other side he didnt change the sign

Step-by-step explanation:

-8x +32 = 9x-9

-9x - 8x + 32 = 9

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Find the value. Please
IgorC [24]
The cosine ratio is adjacent leg divided by the hypotenuse.
The hypotenuse in a right triangle is the longest side and it is opposite the right angle.
An adjacent leg is the side that has an endpoint that is at the vertex of the angle and the other endpoint is at the vertex of the right angle.

cos A = \frac{12}{20} =  \frac{3*4}{5*4} = \frac{3}{5}
ANSWER: cosA= \frac{3}{5}


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3 years ago
What is the length of chord in O below?
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makenzie earns 12.50 per hour being a lifeguard. how much will she earn in 5 days if she works 7 hours each day
TEA [102]
5(12.50 x 7) = 437.5

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5 0
3 years ago
0.4(2x-9)-0.6(4x+5)=
masha68 [24]

Answer:

From what I can comprehend I believe the answer is <em>3.2x + -4</em>

Step-by-step explanation:

0.4(2x-9) = 0.8x - 9

0.8x - 9 - 0.6(4x+5)=

0.8x - 9 + 2.4x+5

0.8+2.4 = 3.2x

-9 + 5 = -4

3.2x + -4

5 0
3 years ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
3 years ago
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