Y = 2^x and y = log₂x
Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x
y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)
Answer: A, C
Answer:
Step-by-step explanation
x1 = 2, y1 = -2 and m = 3/4
y - y1 = m(x - x1)
y - (-2) = 3/4(x - 2)
y + 2 = 3/4(x - 2)
Multiply each term by 4
4y + 8 = 3(x - 2)
4y + 8 = 3x - 6
4y = 3x - 6 - 8
4y = 3x - 14
Answer:
n<7
Step-by-step explanation:
hope i did okay for you
Answer:
4.(a) y = -2x + 5
Step-by-step explanation:
