Manuel estimates that 2/3 of a pizza is left. Stephen estimates that 3/4 is left. They are

There are 12 bags in a box of popcorn that cost $8.25. Find the unit rate for ONE bag of popcorn. Round to the hundredths place.

goldfiish [28.3K]

Answer:

$0.69 for each bag

Step-by-step explanation:

Since you have 12 bags for $8.25, that means you need to divide the price by the number of bags to get the price of each:

$\frac{8.25}{12} = 0.6875$

You then need to round to the nearest hundredths. Since the number after the hundredths place is a 7, which is greater than or equal to 5, you need to add 1 to the hundredths place making the final answer $0.69

7 0

3 years ago

Find the 12th term of an AP of the form 7, 12, 17, 22

ikadub [295]

Answer: 62

Step-by-Step Explanation:

First Term (a) = 7
Common Difference (d) = 12 - 7 = 5
Term to Find (n) = 12th

Therefore, finding the 12th Term :-
=> a+(n-1)d
= 7 + (12 - 1)5
= 7 + (11)5
= 7 + 55
=> 62

Hence, 12th Term of this AP is 62

4 0

2 years ago

Read 2 more answers

~Please help, 50 Points, and Brainliest if correct!~

algol13

A is the correct answer you are looking for

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6 0

3 years ago

Read 2 more answers

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

Find the average rate of change of the function f(x), represented by the graph, over the interval [0, 3]. Calculate the average

Over [174]

Answer:

[f(3) - f(0)]/(3-0)

[f(3) - f(0)]/3

7 0

3 years ago