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DENIUS [597]
3 years ago
6

In baseball, David has 10 hits out of 14 at bats. Adam has 15 hits out of 21 at bats. For each player, write a ratio that repres

ents his total number of hits out of times at bat.
Are these ratios equivalent?
Mathematics
1 answer:
evablogger [386]3 years ago
6 0

Answer:

sorry I don't know......

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7 pens and 20 pencils because 28 divided by 4 = 7 and 80 divided by 4 = 20






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3 years ago
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Find the area of trapezoid JKLM. Round the answer to the nearest tenth.
maksim [4K]

from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.

likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}

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2 years ago
The tiger at the zoo ate 133 pounds of food in 7 days find the average change in the zoos tiger food supply each day
vfiekz [6]

Which describes the effect of the transformations on the graph of ƒ(x) = x2 when changed to ƒ(x) = 3(x + 2)2 − 4?

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C) compressed vertically, shifted left 2 units, and shifted down 4 units  

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5 0
3 years ago
Can someone help me? :(<br><br>​
aleksandr82 [10.1K]

Answer:

0.037037037037037 i think

Step-by-step explanation:

3 0
3 years ago
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A local grocery store chain has a sushi stand. That sushi stand makes samples for store customers to entice customers to purchas
Liula [17]

Answer: 0.99822

Step-by-step explanation:

Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.

So converting 14 into minutes will give  \frac{14}{60}=0.233

Let X=inter-arrival time between two customers

and here \lambda = 0.233

Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)

Now the Poisson distribution has PDF = \frac{\exp ^{-\lambda }\times \lambda ^{X}}{X!}

So P(X = 0) = \frac{\exp ^{-0.233}\times 0.233^{0}}{0!} = 0.79215

P(X= 1) = \frac{\exp ^{-0.233}\times 0.233^{1}}{1!} = 0.18457

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Now adding all three probability gives =  0.79215 +0.18457 + 0.02150=0.99822

3 0
3 years ago
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