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Ira Lisetskai [31]
2 years ago
7

Which factor pair does not belong to 36

Mathematics
1 answer:
vekshin12 years ago
7 0

Answer:

36 is a composite number as it has factors other than 1 and itself. Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. Pair factors of 36 are (1, 36), (4, 9), (6, 6), (12, 3), and (18, 2). 1 is a factor of every number.

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The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
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(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

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y = 6x + 6    The slope of this line is 6, so the parallel line's slope is also 6.

Now that you know m = 6, substitute/plug it into the equation:

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y = 6x + b     To find "b", plug in the point (20, 1) into the equation

1 = 6(20) + b

1 = 120 + b       Subtract 120 on both sides to get "b" by itself

1 - 120 = 120 - 120 + b

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An example of the ratio 4:1 could be, in a school for every 4 girls there is 1 boy. Or something similar:)
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Step-by-step explanation:

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