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telo118 [61]
3 years ago
8

In a typical day, what types of Computer-Mediated Communication do you use?

Computers and Technology
1 answer:
inn [45]3 years ago
8 0

Answer:

Well, the types of Computer-Mediated communication I use are email, network communication and distance learning.

Explanation:

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To construct a battery with a current of 6 A, you would connect six 1 A cells
Eva8 [605]

in series i believe

6 0
3 years ago
Which form of malware contains hidden code that is triggered by meeting or reaching a specific condition? (A) Trap door (B) Viru
Alborosie

Answer:

D- Trojan Horse

Explanation:

Trojan horse is a malware that has hidden code and look legitimate in order to damage or transfer harmful action on the computer.

Example hackers can disguise as Trojan horse by spying on the victims computer in order to gain access to sensitive data on the computer over the network.

3 0
3 years ago
A typical setup for a ____ network would include computer users sharing a single internet connection.
konstantin123 [22]
Could be 'home or work' or intranet. Not enough context to answer any better.
3 0
4 years ago
(5 pt.) The name of a variable in the C programming language is a string that can contain uppercase letters, lowercase letters,
lilavasa [31]

Answer:

The different variable in C is 21213316700.

Explanation:

Given value:

Total value  = letters + underscore value

Total value  = 52 + 1

Total value =53

choice for first character = 53 letters +10 digits

first character = 63

choice for remaining characters

So,

Variable number With one 1 character = 53

Variable number With 2 character  = 53 × 63

Variable number With 3 character = 53 × 63²

Variable number With 4 character  = 53 × 63³

.

.

.

Variable number With 7 character  = 53 \times  63^{7}

Total difference variable = 53 + 53 × 63+ 53 × 63²+ 53 × 63³+....+ 63^{7}

Total difference variable = 53(1 + 63 + 63²+ 63³+ .... + 63^{7})

Formula:

1+x+x^2+x^3+x^4+........x^n\\\\\Rightarrow  \frac{x^{(n+1)} -1}{x-1}

Total difference variable

53 \times \frac{63^{7+1} -1 }{63-1}\\\\53 \times \frac{63^{8} -1 }{63-1} \\\\ \therefore 63^8 = 2.48 \times 10^{14}\\\\53 \times \frac{2.48 \times 10^{14} -1  }{62}\\\\53 \times \frac{1.48 \times 10^{14}}{62}\\\\21213316700

6 0
4 years ago
Write the code to declare a variable to hold the value of the grade you hope to get in this class. What stdio.h input function w
GREYUIT [131]

Answer:

// code to read grade

#include <stdio.h>

// main function

int main(void) {

   // if grade is character

char grade;

// if grade is numeric then we can use int or double

// int grade;

// double grade;

printf("Enter your grade:");

// read grade from user

scanf("%c",&grade);

// print grade

printf("your grade is:%c",grade);

return 0;

}

Explanation:

To read a value, scanf() function is used from stdio.h.Read a grade from user and assign it to variable "grade".

Output:

Enter your grade:A

your grade is:A

// code to read die volt

#include <stdio.h>

// main function

int main(void) {

// variable

double die_volt;

printf("Enter die volt:");

// read die volt from user

scanf("%lf",&die_volt);

// print die volt

printf("Entered die volt is:%0.2lf",die_volt);

return 0;

}

Explanation:

Read the die volt from user and assign it to variable "die_volt" with the help

of scanf() function.

Output:

Enter die volt:220                                                                                                        

Entered die volt is:220.00

4 0
4 years ago
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