2 years ago

What is the total displacement of the object?

Mathematics

1 answer:

Yanka [14]2 years ago

3 0

Answer:

562.5

Step-by-step explanation:

A = ½ (10 m/s + 35 m/s) (25 s)

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There is a bag filled with 3 blue, 4 red and 5 green marbles. A marble is taken at random from the bag, the colour is noted and

aliina [53]

Answer:

i think the answer is 9.

Step-by-step explanation:

8 0

2 years ago

If the bases of a trapezoid have lengths of 19 and 38, what is the length if the median?

Feliz [49]

Length of the median would be: a+b / 2 = 19+38 / 2 = 57/2 = 28.5

7 0

2 years ago

The area of the isosceles triangle is 80 square centimeters. Use the equation 1/2(8h) =80 to find the height of the triangle.

Dmitry [639]

Answer:

20cm

Step-by-step explanation:

Given data

Area= 80cm^2

we know that the expression for the area of a triangle is

A= 1/2B*H

from the given expression 1/2(8h) =80 the base is 8cm

let us substitute to find the height h

1/2(8h) =80

4h=80

h= 80/4

h= 20cm

Hence the heigth h is 20cm

6 0

2 years ago

Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?

Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

$\sin^2 \theta +\cos^2 \theta = 1$

Let us solve this equation for cosine function.

$\cos^2 \theta = 1-\sin^2 \theta$

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

$\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}$

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

$\cos \theta=\sqrt{1-\sin^2 \theta}$

Thus, the correct option is: True; quadrants I & IV

6 0

2 years ago

Read 2 more answers

Find the arc length of a central angle of pi/4 in a circle whose radius is 8 inches

xxTIMURxx [149]

The arc length will be given by:
C=Θ/360πd
where:
Θ=45
d=8*2=16 in
hence;
C=45/360*π*16
=6.3 inches

8 0

2 years ago