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2 years ago

1. what two things need to be true in order to add/subtract two radicals ?

1 answer:

6 0

Answer: 1. To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.2.The index tells you how many of a kind you need to put together to be able to move that number or variable from inside the radical to outside the radical. For example, if the index is 2 (a square root), then you need two of a kind to move from inside the radical to outside the radical.3.When factoring a trinomial in the form x2 + bx + c, consider the following tips. Look at the c term first. o If the c term is a positive number, then the factors of c will both be positive or both be negative. In other words, r and s will have the same sign.

Step-by-step explanation:

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PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago

Can anybody help this question?

Oxana [17]

Answer:

the first option

Step-by-step explanation:

really, just look at the table.

is the mean value (10.4) larger than the median (13.4) ?

I hope you can see right away that it is not.

and you can see they are not the same either.

so, all the answer options mentioning mean larger than median or equal to median can be ruled out right away.

so, it is between the first two options.

now think ! how do we draw number lines ? a coordinate axis ?

the smaller numbers left, the larger numbers right. the numbers grow from left to right.

the mean value is simply the sum of all measurements divided by the number of measurements (how many median were done). if that is smaller that the median (so, the Mean is left of the Median), it means that the majority of measurements had a result smaller (to the left) than the Median. so, it is skewed-left.

6 0

2 years ago

Verify identity : <img src="https://tex.z-dn.net/?f=2%20%5Csin%20%7B%7D%5E%7B2%7D%20%28%20%5Calpha%20%29%20%20%2B%20%20%5Cco

ruslelena [56]

Answer:

what is this? math or physics?

Step-by-step explanation:

7 0

2 years ago

Which of the following is a simpler way to write cos/sin tan sec csc cot

Yuri [45]

This one is really simple
cot

8 0

2 years ago

Read 2 more answers

Can you guys help..please

sergij07 [2.7K]

Answer:

Step-by-step explanation:

IV does not represent y as the function of x since the ordinates share the same abscissa. As we can see in the graph {(4,-1),(4,4),(-4,-1),(-4,4)}

Mark me as brainliest char

5 0

2 years ago