All categories

2 years ago

1. what two things need to be true in order to add/subtract two radicals ?

1 answer:

6 0

Answer: 1. To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.2.The index tells you how many of a kind you need to put together to be able to move that number or variable from inside the radical to outside the radical. For example, if the index is 2 (a square root), then you need two of a kind to move from inside the radical to outside the radical.3.When factoring a trinomial in the form x2 + bx + c, consider the following tips. Look at the c term first. o If the c term is a positive number, then the factors of c will both be positive or both be negative. In other words, r and s will have the same sign.

Step-by-step explanation:

You might be interested in

Out of 460 students 60% have pets how many of the students have pets

Butoxors [25]

276 is the answer because 460 times .6 = 276

6 0

3 years ago

Read 2 more answers

Find the solution of the given initial value problem: y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago

3. The price of a pair of shoes is $64.00 plus 9% sales tax. What is the sales tax on this pair of shoes in dollars and cents? A

Luden [163]

Step-by-step explanation:

To figure out this answer, you need to figure out how much 9% is in $64.00

? 9

------- = --------

64 100

Now to solve this you have to multiply diagonally and divide the neighbor

(let me explain)

basically in this case, you would multiply 64 and 9, then divide by 100

64 * 9 = 576

576 / 100 = $5.76

In short: your answer is 'A' $5.76

Hope this helps <3

8 0

3 years ago

What is the lcm of 9 12 and 18

Luda [366]

The LCM for this is 3.

8 0

3 years ago

Read 2 more answers

Luis wants to buy a skateboard that usually sells for $79.20. All merchandise is discounted by 12%. What is the total cost of th

Contact [7]

Answer:

$74.75

Step-by-step explanation:

When it comes to tax, the sales tax is applied after the discount is provided by the store, as long as it is something like a direct store coupon or a discounted price. In this case, it is a discounted price by the store, so we will include sales tax after.

$79.20 after a 12% discount becomes $69.70 (or $69.696).

The state tax applies to this new price.

7.25% of $69.70 is $74.75

5 0

3 years ago