Price of one adult ticket is $9 and price of one student ticket is also $9.
Step-by-step explanation:
Let,
Adult ticket = x
Student ticket = y
According to given statement;
x+2y=27 Eqn 1
2x+2y=36 Eqn 2
Subtracting Eqn 1 from Eqn 2;

Putting x=9 in Eqn 1;

Dividing both sides by 2;

Price of one adult ticket is $9 and price of one student ticket is also $9.
Keywords: linear equations, subtraction
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Area of base
So possible dimensions are optionB given
Verified
Apply Pythagoras:
length = sqrt( (10--4)² + (6-3)² ) = sqrt(205)
Given:
side length = 6 ft
To find:
The area of the figure
Solution:
Area of the square = side × side
= 6 × 6
Area of the square = 36 ft²
Diameter of the semi-circle = 6 ft
Radius of the semi-circle = 6 ÷ 2 = 3 ft
Area of the semi-circle = 

Area of the semi-circle = 14.13 ft²
Area of the figure = Area of the square - Area of the semi-circle
= 36 ft² - 14.13 ft²
= 21.87 ft²
Area of the figure = 21.9 ft²
The area of the figure is 21.9 ft².
Answer:
it would be b
Step-by-step explanation: