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Artist 52 [7]
2 years ago
10

Solve for T=C(6+AB) for A

Mathematics
1 answer:
valkas [14]2 years ago
3 0

Answer:

a=t 6

__ - ___

cb b

Step-by-step explanation:

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In the expression 852.763 x 10?, what is the missing exponent that would result in a number that is 1,000 times the value of 852
Molodets [167]

Answer:

The missing exponent = power of 3

852.763 x 10³ = 852763

Step-by-step explanation:

The expression 852.763 x 10?

A number that is 1,000 times the value of 852.763 is calculated as:

852.763 × 1000 = 852763

Converting this to exponent

852.763 × 10³ = 852763

Therefore, the missing exponent that would result in number that is 1,000 times the value of 852.763 is power of 3 meaning 10³

7 0
2 years ago
Natalia is making a pizza. The radius of the pizza is 25 inches. What is
aniked [119]

(b)(b)=25 cm2

b2=25 cm2

√(b2)=√(25 cm2)

b= 5 cm

Please note the square root of 25 was taken, as well as the square root of cm2.

Perimeter=4b

Perimeter=4(5 cm)

Perimeter=20 cm

Step:

A circle of radius = 12.5 or diameter = 25 or circumference = 78.54 cm has an area of: 4.909 × 10-8 square kilometers (km²) 0.04909 square meters (m²)

8 0
3 years ago
I need help finding area of this shape
quester [9]

Answer:

170

Step-by-step explanation:

30 x 3 then do 10 x 8

90 + 80

5 0
3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
Find the 6th term . <br>16,48,144​
olga55 [171]

Step-by-step explanation:

a=16

r=3

48/16=3

144/16=3

6th term

=ar^(n-1)

= 16(3)^(6-1)

=3888

5 0
2 years ago
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