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yaroslaw [1]
2 years ago
10

Will mark brainiest Please help

Mathematics
1 answer:
mario62 [17]2 years ago
5 0

Answer:

This is rlly confusing

Step-by-step explanation:

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5x-25=-10<br><br> Please HELP
solong [7]

Answer:

We simplify the equation to the form, which is simple to understand  

5x+25=10

We move all terms containing x to the left and all other terms to the right.  

+5x=+10-25

We simplify left and right side of the equation.  

+5x=-15

or this is another way

Simplifying

5x = 25 + -10

Combine like terms: 25 + -10 = 15

5x = 15

Solving

5x = 15

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '5'.

x = 3

Simplifying

x = 3

We divide both sides of the equation by 5 to get x.  

x=-3

3 0
3 years ago
Read 2 more answers
The triangles are similar what is the value of x
sveticcg [70]
Is one of your options 240

8 0
3 years ago
The gcf of two numbers less than or equal to 12 is 2. Their LCM is 20.What are the numbers?
bixtya [17]

We know:

LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}

We have

GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12

Substitute:

20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40

40=1\cdot40=2\cdot20=4\cdot10=5\cdot8

Only 4 and 10 meet the requirements of the question.

--------------------------------------------------------------------

40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

5 0
3 years ago
If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
mihalych1998 [28]
Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
Alvin is 14 years older than elga's The sum of their ages is 94 what is elga'ss age
Sonja [21]
Elga’s age is 40 and Alvin’s age is 54
8 0
3 years ago
Read 2 more answers
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