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drek231 [11]
3 years ago
6

which equation results from isolating a radical term and squaring both sides of the equation for the equation

Mathematics
2 answers:
damaskus [11]3 years ago
4 0

Answer:

D) c - 2 = 25 + c + 10√c

Step-by-step explanation:

The given equation is \sqrt{c - 2} - \sqrt{c}  = 5

\sqrt{c -2} = 5 + \sqrt{c} \\

Taking square on both sides, we get

Here we used ( a+ b)^2 = a^2 + b^2 + 2ab formula.

c - 2 = 5^2 + (√c)^2 + 2(5)√c

c - 2 = 25 + c +10√c

Answer: D) c - 2 = 25 + c + 10√c

Thank you.

SashulF [63]3 years ago
4 0

Answer:

D. c-2=25+c+10\sqrt{c}

Step-by-step explanation:

We have been given a radical equation \sqrt{c-2}-\sqrt{c}=5. We are asked to find the equation that results from isolating a radical term and squaring both sides of the equation for the equation.

Add \sqrt{c} on both sides:

\sqrt{c-2}-\sqrt{c}+\sqrt{c}=5+\sqrt{c}

\sqrt{c-2}=5+\sqrt{c}

Square both sides:

(\sqrt{c-2})^2=(5+\sqrt{c})^2

Using radical rule \sqrt[n]{a^n} =a, we will get:

c-2=(5+\sqrt{c})^2

Using perfect square formula (a+b)^2=a^2+2ab+b^2, we will get:

c-2=5^2+2*5\sqrt{c}+(\sqrt{c})^2

c-2=25+10\sqrt{c}+c

c-2=25+c+10\sqrt{c}

Therefore, option D is the correct choice.

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