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3 years ago

Need help plsss tyyyyyy

Mathematics

2 answers:

QveST [7]3 years ago

7 0

Answer:

option 4

Step-by-step explanation:

let the side of the square be s , then

length of rectangle = s + 14 and width = s - 4

Since the areas are equal then

s² = (s + 14)(s - 4) ← distribute using FOIL

s² = s² + 10s - 56 ( subtract s² - 56 from both sides )

56 = 10s ( divide both sides by 10 )

5.6 = s

Then

area of square = s² = 5.6² = 31.36 cm²

LenKa [72]3 years ago

5 0

Answer:

the answer is the third one. I calculated the work on my phone and also did it on paper to check and make sure my work was correct!

Step-by-step explanation:

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A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let P(A) be the probability that goggle of type A is manufactured

P(B) be the probability that goggle of type B is manufactured

P(E) be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

P(A) = 30%

P(B) = 70%

P(E/A) is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

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