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Zinaida [17]
3 years ago
11

Find the volume of the cone. H=9cm r=6cm

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

Volume is 339.29cm

Step-by-step explanation:

never [62]3 years ago
3 0

Answer:

the volume of the cone is 339.29

Step-by-step explanation:

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Answer:

I do not know

Step-by-step explanation:

I think so

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2 years ago
Rationalize the denominator, then simplify 10/sqrt2
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5\sqrt{2}

Step-by-step explanation:

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Use the numbers below to simplify the expression. Numbers may be used once or not at all. 34671011 3y + 7 + 4y + 3 = y +
Svetllana [295]

Answer:

3y + 7 + 4y + 3 = 7y + 10

Step-by-step explanation:

Given

3y + 7 + 4y + 3 = [\ ]y + [\ ]

Required

Simplify

We have:

3y + 7 + 4y + 3

Collect like terms

3y + 7 + 4y + 3 = 3y + 4y + 7 + 3

Evaluate like terms

3y + 7 + 4y + 3 = 7y + 10

8 0
3 years ago
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
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