Answer:
I do not know
Step-by-step explanation:
I think so
Answer:

Step-by-step explanation:
To rationalize the denominator, you need to multiply the numerator and denominator by the radical in the denominator (aka. a factor of 1):




Answer:

Step-by-step explanation:
Given
![3y + 7 + 4y + 3 = [\ ]y + [\ ]](https://tex.z-dn.net/?f=3y%20%2B%207%20%2B%204y%20%2B%203%20%3D%20%5B%5C%20%5Dy%20%2B%20%5B%5C%20%5D)
Required
Simplify
We have:

Collect like terms

Evaluate like terms

Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo