Well pick an answer and press submit
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Answer:
(1,6)
x = 1, y = 6
See attachment for the graph
Step-by-step explanation:
y=x+5
y=-x+7
Using the elimination process
y=x+5
- y=-x+7
----------------
0=2x-2
2=2x
1=x
x=1
Substitute x = 1
y = x + 5
y = 1 + 5
y = 6
A circle with equation:
( x + 3 )² + ( y - 2 )² = 36
Center of a circle: C ( - 3, 2 )
r = 6 ( the radius of a circle stays the same )
After shifting 3 units left : C 1 ( - 6, 2 ).
Answer:
( x + 6 )² + ( y - 2 )² = 36
