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user100 [1]
3 years ago
8

Two poles of lengths 10 ft and 15 ft are set up vertically with bases on horizontal ground 12 ft apart. Find the distance betwee

n the tops of poles
Mathematics
2 answers:
miskamm [114]3 years ago
8 0

Answer:

13 ft.

Step-by-step explanation:

We have a right triangle with base 12, height = 15 -10 = 5 and we need to find the hypotenuse which is the distance between the 2 tops.

x^2 = 5^2 + 12^2 = 144 + 25 = 169.

x = sqrt169 = 13 ft.

svp [43]3 years ago
5 0

The distance between the tops of the poles is the hypotenuse of the triangle which is equal to the square root of (12^2 + 5^2)

The hypotenuse = square root (144 + 25) = 13 ft

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The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl
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<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

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<u>Explanation</u>:-

<em>Given sample size 'n' = 517</em>

Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.

'x' =211

<em>The sample proportion</em>

                                   p^{-}  = \frac{x}{n} = \frac{211}{517} =0.4081

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<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(p^{-}  - Z_{\frac{\alpha }{2}  } \sqrt{\frac{p^{-} (1-p^{-} )}{n} } , p^{-} + Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} }{n} } )

(0.4081  - 2.326   \sqrt{\frac{0.4081 (0.5919 )}{517} } , 0.4081+ 2.326\sqrt{\frac{0.4081(0.5919 }{517} } )

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<u><em>Conclusion</em></u>:-

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

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