Question

12

Answer 1

Step-by-step explanation

Answer 2

Step-by-step explanation:

$\tt{2 {x}^{2} + 5x - 3 = 0}$

⇢ $\sf{2 {x}^{2} + 5x + ( - 3) = 0}$

Here , a = 2 , b = 5 & c = -3 {a is the coefficient of x² , b is the coefficient of x and c is the constant term }

Now ,

$\tt{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }$

⇢ $\tt{x = \frac{ - 5± \sqrt{ {5}^{2} - 4 \times 2 \times ( - 3) } }{2 \times 2} }$

⇢ $\sf{ x= \frac{ - 5±7}{4} }$

Taking positive ( + ) sign :

⇝$\tt{x = \frac{ - 5 + 7}{4} = \frac{1}{2}}$

Taking negative ( - ) sign :

⇝$\tt{x = \frac{ - 5 - 7}{4} = - 3}$

$\purple{ \boxed{ \boxed{ \tt{⤑ \: Our \: final \: answer : \boxed{ \underline{ \tt{x = \frac{1}{2} , \: - 3}}}}}}}$

Hope I helped ! ツ

Have a wonderful day / night♡

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