Answer:B
Step-by-step explanation:
The quadratic formula can be used to solve an equation only if the highest degree in the equation is 2
Part (a)
There are 7 red out of 7+3 = 10 total
<h3>Answer: 7/10</h3>
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Part (b)
We have 3 green out of 10 total
<h3>Answer: 3/10</h3>
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Part (c)
3/10 is the probability of getting green on any selection. This is because we put the first selection back (or it is replaced with an identical copy)
So (3/10)*(3/10) = 9/100 is the probability of getting two green in a row.
<h3>Answer: 9/100</h3>
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Part (d)
Similar to part (c) we have 7/10 as the probability of getting red on each independent selection.
(7/10)*(7/10) = 49/100
<h3>Answer: 49/100</h3>
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Part (e)
7/10 is the probability of getting red and 3/10 is the probability of getting green. Each selection is independent of any others.
(7/10)*(3/10) = 21/100
<h3>Answer: 21/100</h3>
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Part (f)
We have the exact same set up as part (e). Notice how (7/10)*(3/10) is the same as (3/10)*(7/10).
<h3>Answer: 21/100</h3>
Answer:C 5a^2 +70a +240
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let
be the number of bags with 8 onions and let
be the number of bags with 3 onions. We have the following system of equations:

Subtracting
from both sides of the first equation, we get
. Substitute this into the second equation:

Therefore, the number of 8-onion bags is:

Thus, the chef got 4 8-onion bags and 3 3-onion bags.
<h3>
Answer: B. (-1, 0)</h3>
This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.
In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality
true. So this is why we can rule choice A out.
Choice C is not a solution because (4,1) does not make
true. This point is not below the red diagonal line. We can cross choice C off the list.
Choice D is similar to choice A, which is why we can rule it out as well.