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sergiy2304 [10]
4 years ago
5

What is the measure of ∠ABC ?

Mathematics
2 answers:
PtichkaEL [24]4 years ago
7 0

Answer:

m∠ACB = 32°

Step-by-step explanation:

It is given in the question that AC is tangent on a circle at A.

m∠ACB = 58° then we have to tell the measurement of ∠ABC.

In ΔABC, ∠BAC = 90° (since radius of a circle is always ⊥ to the tangent drawn)

Therefore in ΔABC

∠ABC + ∠BAC + ∠ACB = 180°

∠ACB + 90 + 58 = 180

∠ACB = 180 - (90 + 58) = 180 - 148 = 32°

Finally m∠ ACB = 32° is the answer.

il63 [147K]4 years ago
5 0
I think the answer is 32 degrees but i am not 100% sure
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Answer:

Step-by-step explanation:

159.39(1-25/100)

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3 years ago
Find the volume of each question in the picture:
Kisachek [45]

Answer:

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Step-by-step explanation:

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V=pi*6^2*13           V=2/3*pi*6^3

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3 years ago
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8 0
3 years ago
Form quadratic functions given the following information:
nignag [31]

Answer:

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or

f(x)=-\frac{4}{7}(x^2-6x+7)

Step-by-step explanation:

we have

f(3+√2 )=f(3− √2 )=0

so

x1=3+√2 and x2=3−√2 are the roots or x-intercepts of the quadratic equation

The quadratic equation in factored form is equal to

f(x)=a(x-x1)(x-x2)

substitute

f(x)=a(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

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f(1)=−8

so

For x=-1 -----> f(x)=-8

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apply difference of squares

-8=a(14)

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therefore

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simplify

Applying distributive property

f(x)=-\frac{4}{7}(x^2+\sqrt{2}x-3x-\sqrt{2}x-2+3\sqrt{2}-3x-3\sqrt{2}+9)

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