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seraphim [82]
3 years ago
12

Help with this math question plz

Mathematics
1 answer:
PtichkaEL [24]3 years ago
5 0

Answer: The length of LK is 40.

Step-by-step explanation:

LK = 6x+10

KM = 2x+8

LM = 58

so

LM = LK + KM

or, 58 = 6x+10+2x+8

or, 58 = 8x + 18

or, 58-18 = 8x

or, 8x = 40

so, x = 5

now

LK = 6x + 10

     = 6*5+10

     = 30 +10

     = 40

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OlgaM077 [116]

Answer:

C

Step-by-step explanation:

Keep a consistent ratio of 4:2, and we need a total of 36 glasses of punch.

So if the ratio 4:2 is a total of 6, then we would need 6 times the amount because 6*6 is 36. So 4 and 2 * 6 or 6 (4+2) = 24+12. So the answer is C.

Hope this helps in some way.

4 0
3 years ago
Read 2 more answers
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agasfer [191]

Answer: 100

Step-by-step explanation:

4(5)^5

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3 years ago
Please! I need help now.​
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The answer is no because she only got information from one group and she should get the input of other 7th graders
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what is the slope of the line that passes through the points (-3,1) and( 7,-14)? write your answer in simplest from.
Harrizon [31]

Answer:

slope = m = (0--3)/(14--4) = 3/18 = 1/6

y=mx + b

y =(1/6)x + b

0= (1/6)14 + b

b = - 14/6 = - 7/3

y = (1/6)x - 7/3

or

6y-x = -14

Step-by-step explanation:

3 0
3 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

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\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
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