For this case we must find

By definition we have to:

We have the following functions:

Now, applying the given definition, we have:

Answer:

Answer:
B. 21.2
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
A(-4, 1)
B(-2, 3)
C(3, -4)
✔️Distance between A(-4, 1) and B(-2, 3):




AB = 4 units
✔️Distance between B(-2, 3) and C(3, -4):




BC = 8.6 units (nearest tenth)
✔️Distance between A(-4, 1) and C(3, -4):




AC = 8.6 units (nearest tenth)
Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units
Answer:
tu aimes les hommes
Step-by-step explanation:
Answer:
The length of rectangle is
The width of rectangle is
Step-by-step explanation:
Let
x-----> the length of rectangle
y----> the width of rectangle
we know that
The area of rectangle is equal to


so
-----> equation A
-----> equation B
substitute equation B in equation A and solve for y

using a graphing calculator
The solution is

Find the value of x
----->