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Ratling [72]
3 years ago
14

The Electrotech Corporation manufactures two industrial-sized electrical devices: generators and alternators. Both of these prod

ucts require wiring and testing during the assembly process. Each generator requires 2 hours of wiring and 1 hour of testing and can be sold for a $250 profit. Each alternator requires 3 hours of wiring and 2 hours of testing and can be sold for a $150 profit. There are 260 hours of wiring time and 140 hours of testing time available in the next production period and Electrotech wants to maximize profit. Suppose that Electrotech's management decides that they need to make at least 20 generators and at least 20 alternators.
Select the correct LP model to account for this change.
Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

X1 = number of generators, X2 = number of alternators

Step-by-step explanation:

Hope this helps!

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A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. What is the probability tha
KiRa [710]

Answer:

Since there are 2 possibilities for each bat (hit or out), the amount of total possibilities is 2 * 2 * 2 = 8. There is only one possibility out of those eight that gives us three hits, therefore the probability is 1 / 8 or 0.125.

4 0
3 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
Iff (x) = 3x + 2 and g(x) = x? – x, find the value.<br> =<br> f (4)
earnstyle [38]
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I hope this helps (:
5 0
3 years ago
Please help me with my question!!!
jeka57 [31]

Answer:

64

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
I need help asapppp!!!!
KIM [24]

Answer:

Your answer is D

Step-by-step explanation:

6 0
3 years ago
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