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BabaBlast [244]
3 years ago
13

Racheal used a total of 5 1/6 gallons of gas while driving her car. Each hour she was driving, she used 5/9 gallons of gas. What

was the total number of hours she was driving ?
Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:  The correct answer is:  " 9.3 hours " .

_________________________________

Step-by-step explanation:

_________________________________

To calculate:

Let "gal" represent "gallons (of gas)" ;

Let "h" represent "hour(s)" ;

________________________________

 5 \frac{1}{6}  gal  * (  <u> 1 h    </u>  )     =  ?  h   ;

                ( 5/9 gal  ) ;

________________________________

<u> Note</u>: On the "left-hand side" of the equation;

           The units of "gal" ["gallons"] — "cancel out" ;

         →  {since:  "gal/ gal = 1"} ;

____________________________

and we can rewrite our equation as:

_____________________________

 ( 5 \frac{1}{6}  )      

________   hours  ;

 ( 5/9 )    

______________________________ ;

To solve:

_____________________________

5  1/6  ÷ (5/9)  =

   5  1/6 * (9/5) ;

____________________________

<u>Note</u>:  Dividing by a fraction is the same as multiplying by that very fraction's reciprocal form.

__________________________

Now, let us convert "5 1/6" ; which is a "mixed fraction" ; into an

"Improper fraction" ;

__________________________

To do this, we can use the "MAD" method:

__________________________

M:  Multiply the "denominator number" of the "fraction portion" [within the "mixed fraction"]—by the "whole number" [within the "mixed fraction" ;   In this case:  "6" , multiplied by "5" ; to get "30" ;

_________________

Then:

_________________

A: Add this obtained value; to the "numerator number" of the

    "fraction portion" [within the "mixed fraction"] ;

      In this case:  "30" ; added to "1" ; to get 31:

__________________

Then:

D:  Divide this number by the  "denominator number" of the "fraction portion" [within the "mixed fraction"] ; but instead of solving for the quotient—write in the format of a fraction:

 In this case:  " \frac{31}{6} " .

_________________________

Now, substitute this "improper fraction" into our original problem; and rewrite:

_________________________

 " \frac{31}{6} * \frac{9}{5} " hours;

_________________________

We can reduce the "9" to "3" ; and the "6" to "2" ;

_________________________

{Since "9/6 = 3/2" };

_________________________

And rewrite as:

_________________________

" \frac{31}{2} * \frac{3}{5} " hours ;

_________________________

Note:  " \frac{31}{2} * \frac{3}{5} " ;

_________________________

 = " \frac{(31*3)}{(2*5)} = \frac{93}{10}  " ;

_________________________

 =  93 ÷ 10 ;  

_________________________

  =  9.3 hours.

_________________________

The answer is:  " 9.3 hours " .

_________________________

Hope this explanation is helpful!

Best of luck to you in your academic pursuits!

_________________________

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