Given that the number of years should be represented with x, the number of fish in the pond after x years should best be represented with f(x). The equation that would best show the given scenario in the problem above is,
f(x) = 500(2^x)
From the given, 500 is used as the initial population of the fish.
Hey there!
You can count from 668 to 900 using the following:
668 → 768 → 868 (two 100s)
868 → 878 → 888 → 898 (three 10s)
898 → 899 → 900 (two 1s)
Hope this helped you out! :-)
Answer:
4/5x + y = -2
Step-by-step explanation:
x^2 - 81 = 0. Add 81 to each side.
x^2 = 81. Take the square root of each side.
x = 9, -9
Answer:
A
Step-by-step explanation:
