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3 years ago

PLEASE HELP ME!! =) NEED DONE NOW.

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

5 0

The answer is a translation of 2 units to the left and 7 units up

Cloud [144]3 years ago

5 0

Answer:

D. a translation of 2 units to the left and 7 units up

just trust me. i got 100!

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which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma

slamgirl [31]

The original expression is given by:
$( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}$
The correct way to rewrite the expression is given by:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
$
For this, we use two properties:

Associative property:
The way of grouping the factors does not change the result of the multiplication:
$\frac{2}{3}*(\frac{1}{5}*\frac{5}{2})$

Commutative property:
The order of the factors does not vary the product:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})$

8 0

3 years ago

If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)

Dahasolnce [82]

Answer: 195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)

As known cos²α=1-sin²α (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17 (2)

Substitute in (1) cosα by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0

3 years ago