2/3
denominator is increased by a number so 3+a
numerator is doubled so 2(2)= 4
in order for it to be a whole (or 1) then it would have to be 4/4
so 4-3=1
the number is 1
Answer:
y(t)= 11/3 e^(-t) - 5/2 e^(-2t) -1/6 e^(-4t)
Step-by-step explanation:
We know that 
, so we have
By using the method of partial fraction we have:
Now we have:
](https://tex.z-dn.net/?f=%20y%28t%29%3DL%5E%7B-1%7D%5BY%28s%29%5D%28t%29%20)
Using linearity of inverse transform we get:
 -L^{-1}[\frac{5}{2(s+2)}](t) -L^{-1}[\frac{1}{6(s+4)}](t)](https://tex.z-dn.net/?f=%20y%28t%29%3DL%5E%7B-1%7D%5B%5Cfrac%7B11%7D%7B3%28s%2B1%29%7D%5D%28t%29%20-L%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B2%28s%2B2%29%7D%5D%28t%29%20-L%5E%7B-1%7D%5B%5Cfrac%7B1%7D%7B6%28s%2B4%29%7D%5D%28t%29%20)
Using the inverse transforms
![L^{-1}[c\frac{1}{s-a}]=ce^{at}](https://tex.z-dn.net/?f=%20L%5E%7B-1%7D%5Bc%5Cfrac%7B1%7D%7Bs-a%7D%5D%3Dce%5E%7Bat%7D%20)
we have:
50 / 0.40 = 125
To check your answer, 125 * 0.4 = 50
Yes 3/4 is bigger than 1/4 3 is bigger than 1 so 3/4 is bigger.
So the problem asks us to find the fraction of your class that plays the saxophone. To find this, all you need to do is divide 2/5 by 1/4. We need to do this because we are basically taking 1/4 of 2/5. When we do this operation, we get 8/5, which is 1 3/5 in mixed fraction form. Hence, the solution to your question is 8/5 or 1 3/5 of the fraction of students in the band play the saxophone. Hope this helps!
