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2 years ago

Which graph shows the linear inequality y-2x-4

Mathematics

1 answer:

larisa86 [58]2 years ago

6 0

First:

A graph that starts y< or y> will always be a dashed line, because the points on the line do not make the equality true.

A graph with y≤ or y≥ will have a solid line.

Second,:

If the equation is y<, then the shading will be below the line. (If you were standing on the line, you'd look straight down for the solutions.)

If the equation is y>, then the shading will be above the line. (If you were standing on the line, you'd look straight up for the solutions.)

For your exercise:

Neither A nor B fits that inequality. I hope there are options C and D

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Answer:hey

Step-by-step explanation:

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3 years ago

If ABC and EDC are similar, what is the value<br> of x?<br> A

abruzzese [7]

Answer:

x = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

BC/DC = EC/AC , substitute values

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3 years ago

What is an equation of the line that is perpendicular to y=−23x+5 and passes through the point (2, 11) ?

hichkok12 [17]

Answer:

The equation would be y = 1/23x - 251/23

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -23. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 1/23.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 11 = 1/23(x - 2)

y - 11 = 1/23x - 2/23

y = 1/23x - 251/23

5 0

2 years ago

Read 2 more answers

2. Suppose over several years of offering AP Statistics, a high school finds that final exam scores are normally distributed wit

nirvana33 [79]

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is $s = \frac{6}{\sqrt{n}}$ and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .