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Aleks [24]
3 years ago
6

Which polynomial is in standard form

Mathematics
2 answers:
amid [387]3 years ago
8 0
The answer would be B. Have a nice day!
xenn [34]3 years ago
7 0
B is the one in standard form
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Graph the inequality x≥1.
dangina [55]

Answer:

look at the file

Download pdf
3 0
3 years ago
I need help with this!!!
aev [14]

Answer:

its the first one

Step-by-step explanation:

8 0
3 years ago
Y''-2y'+y=2(e^x)-3(e^-x)
labwork [276]
First find the characteristic solution. The characteristic equation is

r^2-2r+1=(r-1)^2=0

which as one root at r=1 of multiplicity 2. This means the characteristic solution for this ODE is

y_c=C_1e^x+C_2xe^x

For the nonhomogeneous part, you can try a particular solution of the form

y_p=(a_2x^2+a_1x+a_0)e^x+be^{-x}

which has derivatives

{y_p}'=(a_2x^2+(2a_2+a_1)x+a_1+a_0)e^x-be^{-x}
{y_p}''=(a_2x^2+(4a_2+a_1)x+2a_2+2a_1+a_0)e^x+be^{-x}

Substituting into the ODE, the left hand side reduces significantly to

2a_2e^x+4be^{-x}=2e^x-3e^{-x}

and it follows that

\begin{cases}2a_2=2\\4b=-3\end{cases}\implies a_2=1,b=-\dfrac34

Therefore the particular solution is

y_p=x^2e^x-\dfrac34e^{-x}

and so the general solution is the sum of the characteristic and particular solutions,

y=y_c+y_p
y=C_1e^x+C_2xe^x+x^2e^x-\dfrac34e^{-x}
3 0
3 years ago
*No Picture* Find all real zeros of the function y = 2x - 4 a. 2 b. (2, –4) c. −4 d. −2
anygoal [31]

Answer:

a

Step-by-step explanation:

The zeroes of a function are when y = 0 so we can write 0 = 2x - 4 so we have to solve for x and when we do so we get x = 2.

6 0
3 years ago
Make b the subject of this formula. a=9b
USPshnik [31]

Answer:

a = 9b

divide each side by 9

\frac{a}{9} = b

6 0
4 years ago
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