Answer: P=450
Step-by-step explanation:
add 41 to both sides of the equation
419 + 31 = p - 31 + 31
2y/(y²-8y+5) - 1/(y-5)=
2y/(y-5)(y-3) - 1/(y-5)=
Least common multiple=(y-5)(y-3)
2y-1(y-3) / (y-5)(y-3)=
2y-y+3 / (y-5)(y-3)=
y+3 / (y-5)/y-3)
Answer : (y+3) / (y-5)(y-3).
you did right, congratulations!!.
Answer:

Step-by-step explanation:
The formula is

The given series is:

where the first term is a=1 and the common ratio is

We plug in all these values to get:


Answer:
<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>
Step-by-step explanation:
<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>
<em><u>Total ingradiants for one packet of biscuits =</u></em>
<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>
Hope it helped you!
Answer:
1. 1/3 plus 3/6
1/3 is the same as 2/6 so
2/6 plus 3/6 is 5/6
1=5/6
2. 1/4+2/8
2/8 is the same as 1/4 so
1/4 plus 1/4 is 2/4 which is the same as 1/2
2=1/2