First: Slope of -x+2y=42y=x+4y=x/2+2So, m=1/2.
Second: Slope of the perpendicular line: mp=-2.
Third: Find the line with slope -2 and passes through the point (−2, 1)y-y1=m(x-x1)y-1=-2(x+2)y=-2x-4+1y=-2x-3
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(-6)-(+8)-(-12)
-6-8+12
-14+12
-2
Answer:
0
Step-by-step explanation:
Cancel out x-y to x^2-Y^2 and you get x+y-x-y which is 0
Answer:
Option D is the correct option.
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