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Zielflug [23.3K]
3 years ago
12

What’s 1 + 1 and why?

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

Answer:

2

Step-by-step explanation:

you add 1 to 1 and that gives you 2

Verdich [7]3 years ago
3 0

Answer:

The answer is 2

Step-by-step explanation:

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I need help on this.​
SSSSS [86.1K]

Answer:

plot the first point on (0,-4)

from there, rise 2, then run 3

plot another point on (3,-2)

plot another on (6,0), and so on

<em><u>Plz mark as brainliest if correct! Have a nice day!!! </u></em>

<em><u>-Lil G</u></em>

8 0
3 years ago
The vertex of the parabola below is at the point (4, -1). Which of the equations below could be the one for this parabola?  
AlekseyPX

Answer:

The answer is B

Step-by-step explanation:

6 0
3 years ago
Caleb has a mask collection of 400 masks. He keeps 260 of the masks on his wall. What percentage of Caleb's mask collection does
Firlakuza [10]

Answer:

Caleb keeps 65% of his mask collection on the wall.

5 0
3 years ago
Level 4
nignag [31]

132/4 = 33, x = 33 boxes

6 0
3 years ago
Read 2 more answers
Can you explain how to do 13 please
Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
3 0
3 years ago
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