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3 years ago

Which equation could be used to find the value of x in the triangle below?

Mathematics

1 answer:

valkas [14]3 years ago

5 0

Answer:

4x - 12 = 180

Step-by-step explanation:

Sum of the angles of triangle equals 180

x + 12 + 2x - 29 + x + 5 = 180

Simplified

4x - 12 = 180

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chase and sara went to the candy store. chase bought 5 pieces of fudge and 3 pieces of gum for 5.70. sara bought 2 pieces of fud

Vilka [71]

Let, the cost of 1 piece of fudge = x
Cost of a gum = y

System of equations: 5x + 3y = 5.70
2x + 10y = 3.60

Multiply 1st equation by 2, and second by 5,
New equations: 10x + 6y = 11.40
10x + 50y = 18

Now, subtract 1st from 2nd,
44y = 6.60
y = 6.60 / 44
y = 0.15

Substitute it in second equation,
2x + 10(0.15) = 3.60
2x = 3.60 - 1.5
x = 2.10 / 2
x = 1.05

In short, Cost of a Fudge = $1.05 & Cost of a gum = $0.15

Hope this helps!

6 0

3 years ago

Giving brainily if ur correct

frozen [14]

the answer is 60.

all you have to do is multiply all the numbers.

3 × 4 × 5 = 60

first:

multiply two of the numbers together. anything you like.

4 × 3 is 12

and now multiply the left number with the

result.

which is

5 × 12 = 60

8 0

3 years ago

Read 2 more answers

M3+ 3 m3 + 4 m² simplify

Kipish [7]

Answer:

${m}^{3} + {27}^{m} + 4 {m}^{2}$

Step-by-step explanation:

${m}^{3} + {3}^{m 3} + 4 {m}^{2}$

${m}^{3} + {3}^{m \times 3} + 4 {m}^{2}$

${m}^{3} + {3}^{3m} + 4 {m}^{2}$

${3}^{3m} = ({3}^{3} {)}^{m} = {27}^{m}$

➡️ ${m}^{3} + {27}^{m} + 4 {m}^{2}$

5 0

2 years ago

Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$

7 0

3 years ago

jamerra received a $3,00 car loan. she plans on paying off the loan in 2 years. at the end of 2 years, jamerra will have paid $4

leonid [27]

The rate of interest is 75 % per year

Solution:

Given that, Jamerra received a $3,00 car loan

she plans on paying off the loan in 2 years

Jamerra will have paid $450 in interest

Therefore, we get

Principal = $ 300

Number of years = 2

Simple Interest = $ 450

Rate of interest = ?

The simple interest is given by formula:

$simple\ Interest = \frac{p \times n \times r}{100}$

Where,

"p" is the principal and "n" is the number of years and "r" is the rate of Interest

Substituting the given values we get,

$450 = \frac{300 \times 2 \times r}{100}\\\\450 = 3 \times 2 \times r\\\\6r = 450\\\\r = \frac{450}{6}\\\\r = 75$

Thus rate of interest is 75 % per year

5 0

3 years ago