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Greeley [361]
3 years ago
14

What is the area of the enlarged trapezoid?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0
1.5 but I could be wrong I would double check
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Heather is a cashier and she can ring up 36 customers in 24 minutes. At this rate how many minutes does it take to ring up 6 cos
Jet001 [13]

Answer: 4

Step-by-step explanation:

Let's make a table.

So we know that for 24 minutes, Heather can ring up 36 customers. Now, to get 6 customers, you need to divide 36 by 6.

So

36 = 24

/ 6    /6

_______

6 = <u>4</u>

3 0
3 years ago
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A lecture hall contains $20$ chairs, all lined in a row. What is the number of ways that five chairs can be chosen, so that no t
patriot [66]

Answer:

Step-by-step explanation:

If we choose chairs having odd number in the row

no of chairs from which selection is made = 10

no of chairs to be selected = 5

no of ways = 10C₅

similarly if we choose hairs having even numbers only ,

similar to above , no of ways

= 10C₅

Total no of ways

= 2 x 10C₅

= 2 x 10 x 9 x 8 x 7 x 6 / 5 x 4x3 x 2 x 1

= 504 .

6 0
3 years ago
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The current temperature is -7C.The high temperature yesterday was an many degrees about 0C. Which expression could be used to fi
Vinvika [58]
The answer is B because to find the distance between a number from zero you need the absolute value in the expression here it’s -7+7
8 0
3 years ago
I need help on this assignment, I need to find the angles of the blank spaces. Anything is appreciated!
Gre4nikov [31]

Answer:

3: 97

10: 97

9: 83

5: 97

7: 83

16: 97

Im 100% on these answers bc Ive already taken this class :)

7 0
3 years ago
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In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
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