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Andru [333]
3 years ago
11

3x+5y-4=0 what is the slope and y-intercept?

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

3x + 5y - 4 = 0 \\ 3x + 5y = 4 \\ 5y = 4 - 3x \\ y =  \frac{4}{5}  -  \frac{3}{5} x \\ y = mx + c \\ slope = m =  \frac{ - 3}{5}  \\ y \: intersept = c =  \frac{4}{5}  \\ thank \: you

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 If the equation y = 15x + 2 is changed to y = 15x - 4, how will the graph of the line change?
igomit [66]
The y-intercept is changed from 2 to -4.

That means that the point that the graph crosses the y axis has been moved down by 6.

Since the slope of the line has not changed, this just means the graph of the line will be moved down by 6.

Hope this helps!
Your fortune is "When given a difficult choice, trust your gut. If you don't have one, then close your eyes and hope for the best."
6 0
3 years ago
Read 2 more answers
The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
ankoles [38]

Answer:

     2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

  T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

  D_x=T_x\sqrt{T_x}

The mean distance of planet Y can be found using the given relation ...

  T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x

The mean distance of planet Y is increased from that of planet X by the factor ...

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8 0
2 years ago
What’s is the area of the shape?
Ksivusya [100]

so you multiply 6 and 3 and it is 18

4 0
3 years ago
Read 2 more answers
Jason solved the following equation to find the value for x.
Ainat [17]
Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
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5 0
2 years ago
Can someone Please help.
Nastasia [14]
Since it is mid-way you would multiply it by 2 so, 8x2=16
Your answer is 16.
Hope I helped <3
4 0
3 years ago
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