Answer:
(0, 0) and (3, 0)
Step-by-step explanation:
Zeros of any equation means, value of variable x at y = 0.
Given quadratic equation is,
y = -x(x - 3)
For y = 0,
-x(x - 3) = 0
x = 0
And (x - 3) = 0
x = 3
Therefore, x-intercepts of the given quadratic equation will be,
x = 0, 3
Points showing the x-intercepts will be,
(0, 0) and (3, 0)
Solve for d:
(3 (a + x))/b = 2 d - 3 c
(3 (a + x))/b = 2 d - 3 c is equivalent to 2 d - 3 c = (3 (a + x))/b:
2 d - 3 c = (3 (a + x))/b
Add 3 c to both sides:
2 d = 3 c + (3 (a + x))/b
Divide both sides by 2:
Answer: d = (3 c)/2 + (3 (a + x))/(2 b)
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Solve for x:
(3 (a + x))/b = 2 d - 3 c
Multiply both sides by b/3:
a + x = (2 b d)/3 - b c
Subtract a from both sides:
Answer: x = (2 b d)/3 + (-a - b c)
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Solve for b:
(3 (a + x))/b = 2 d - 3 c
Take the reciprocal of both sides:
b/(3 (a + x)) = 1/(2 d - 3 c)
Multiply both sides by 3 (a + x):
Answer: b = (3 (a + x))/(2 d - 3 c)
Finding an angle of a triangle
Answer:
get someone else to do it
Step-by-step explanation:
wish you luck
